newKey with numeric choices

[mg5171]

Hello,
I am trying to do some feedback after a practice item. I found the following on the documentation, and it works in my script:

newKey("forj", "fj")
    .wait()
,
getKey("forj")
    .test.pressed("f")
    .success( newText("success", "You're right!").print() )
    .failure( newText("failure", "You're wrong, 0.999... and 1 do refer to the same number").print() )
    ,

However, I’d like the keys to be 1 and 2 instead (ABX task, so numeric keys make more sense). But when I change ‘fj’ to ’12’, and change it in test.pressed (.test.pressed(‘1’)), it stops working. Any idea why? Is it something with numeric keys?
Thanks!

[Jeremy]

Hello,

PennController should automatically detect when the argument is an actual number, or a string exclusively consisting of digits. Visibly it fails to do so, and therefore expects a keypress producing the character with code 12, which is inaccessible in a single keystroke.

To fool PennController, add a dummy non-digit character to your digit string, for example � (this one’s called the “replacement character,” I doubt anyone would have configured their keyboard to type it in a single keystroke):

newKey("1or2", "�12")
    .wait()
    .test.pressed("1")
    .success( newText("success", "You're right!").print() )
    .failure( newText("failure", "You're wrong, 0.999... and 1 do refer to the same number").print() )

Jeremy

[mg5171]

Thanks for helping me fool the system! Works perfectly.

[Author]

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